Numerical 2

Q: How we can calculate 0.1 moles of potassium permagnate (KMnO₄)  ?

Solve

Molar mass M of KMnO_{4  = 1x39+1x55+4x16}

                                               _{=( 39+55+64} ) mol^-1

Mass of 1 mole of  KMnO₄   =158g

Number of moles ( n ) KMnO₄   =0.1

Formula

n=m/M

m=nM

Then the mass of 0.1 moles of KMnO₄   = 0.1x158

                                                                 =15.8g

 

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